मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

Draw the graph of y = x2 – 4 and hence solve x2 – x – 12 = 0 - Mathematics

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प्रश्न

Draw the graph of y = x2 – 4 and hence solve x2 – x – 12 = 0

आलेख
बेरीज

उत्तर

(i) Draw the graph of y = x2 – 4 by preparing the table of values as below.

x – 4 – 3 – 2 – 1 0 1 2 3 4
x2 16 9 4 1 0 1 4 9 16
– 4 – 4 – 4 – 4 – 4 – 4 – 4 – 4 – 4 – 4
y 12 5 0 – 3 – 4 – 3 0 5 12

(ii) Plot the points for the ordered pairs (– 4, 12) (– 3, 5) (– 2, 0) (– 1, – 3) (0, – 4) (1, – 3), (2, 0), (3, 5) and (4, 12). Draw the curve with a suitable scale.

(iii) To solve x2 – x – 12 = 0 subtract x2 – x – 12 from y = x2 – 4

y = x2 – 0 – 4
0 = x2 – x – 12
     (–)  (+)  (–) 
y = x + 8

The equation y = x + 8 represents a straight line. Prepare a table for y = x + 8

x – 3 – 1 0 2 4
y 5 7 8 10 12

(iv) Mark the point of intersection of the curve and the straight line is (– 3, 5) and (4, 12)

∴ The solution set is (– 3, 4) for x2 – x – 12 = 0.

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पाठ 3: Algebra - Exercise 3.15 [पृष्ठ १३७]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 3 Algebra
Exercise 3.15 | Q 2 | पृष्ठ १३७
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