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Question
`y^2 + 1/y^2` is not equal to
Options
`(y^4 + 1)/(y^2)`
`(y + 1/y)^2`
`(y - 1/y)^2 + 2`
`(y + 1/2)^2 - 2`
Solution
`(y + 1/y)^2`
Explanation;
Hint:
`y^2 + 1/y^2 = (y + 1/y)^2 - 2 xx y xx 1/y` ...[a2 + b2 = (a + b)2 – 2ab]
= `(y + 1/y)^2 - 2 ≠ (y + 1/y)^2`
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