Advertisements
Advertisements
प्रश्न
Height and base of a right angled triangle are 24 cm and 18 cm. Find the length of its hypotenus?
उत्तर
In ∆PQR, ∠Q = 90°
∴ PR2 = PQ2 + QR2 ......[Pythagoras theorem]
= 242 + 182
= 576 + 324
= 900
∴ PR = `sqrt(900)`
= 30 cm
APPEARS IN
संबंधित प्रश्न
Out of the following, which is the Pythagorean triplet?
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Find the height of an equilateral triangle having side 2a.
Do sides 7 cm, 24 cm, 25 cm form a right angled triangle ? Give reason
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm then find RS and ST.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Seg AM is a median of ∆ABC. If AB = 22, AC = 34, BC = 24, find AM
In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2 = 290. Find the length of QR.
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.
Choose the correct alternative:
Out of all numbers from given dates, which is a Pythagoras triplet?
"The diagonals bisect each other at right angles." In which of the following quadrilaterals is the given property observed?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?