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प्रश्न
How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of 1 Ω ?
संख्यात्मक
उत्तर
The following circuit diagram shows the connection of the three resistors.
All the resistors are connected in series. Therefore, their equivalent resistance will be given as
`1/(1/2 + 1/3 + 1/6)`
= `1/((3 + 2 + 1)/6)`
= `6/6`
= 1 Omega
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