Question

How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of 1 Ω ?

Answer 1

The following circuit diagram shows the connection of the three resistors.

All the resistors are connected in series. Therefore, their equivalent resistance will be given as 

`1/(1/2 + 1/3 + 1/6)`

= `1/((3 + 2 + 1)/6)`

= `6/6`

= 1 Omega