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प्रश्न
How is propanoic acid is prepared to start from an alkene?
उत्तर
\[\ce{\underset{(Ethene)}{CH2 = CH2} ->[HCl] \underset{(Ethyl chloride)}{CH3 - CH2 - Cl} ->[NaCN][-NaCl] \underset{(Ethyl cyanide)}{CH3 - CH2 - CN} ->[H^+/H2O][Excess] \underset{(Propanoic acid)}{CH3CH2COOH}}\]
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संबंधित प्रश्न
The IUPAC name of
How is propanoic acid is prepared to start from alcohol?
How is propanoic acid is prepared to start from an alkyl halide?
An alkene (A) on ozonolysis gives propanone and aldehyde (B). When (B) is oxidised (C) is obtained. (C) is treated with Br2/P gives (D) which on hydrolysis gives (E). When propanone is treated with HCN followed by hydrolysis gives (E). Identify A, B, C, D and E.
Oxidation of ketones involves carbon-carbon bond cleavage. Name the product(s) is/are formed on oxidising 2, 5-dimethyl hexan-3-one using a strong oxidising agent.
