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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 12 TN Board chapter 12 - Carbonyl Compounds and Carboxylic Acids [Latest edition]

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Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 12 TN Board chapter 12 - Carbonyl Compounds and Carboxylic Acids - Shaalaa.com
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Solutions for Chapter 12: Carbonyl Compounds and Carboxylic Acids

Below listed, you can find solutions for Chapter 12 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Chemistry - Volume 1 and 2 [English] Class 12 TN Board.


Evaluation
Evaluation [Pages 189 - 194]

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 12 TN Board 12 Carbonyl Compounds and Carboxylic Acids Evaluation [Pages 189 - 194]

Choose the correct answer:

Evaluation | Q 1. | Page 189

The correct structure of the product ‘A’ formed in the reaction is

Evaluation | Q 2. | Page 189

The formation of cyanohydrin from acetone is an example of ____________.

  • nucleophilic substitution

  • electrophilic substitution

  • electrophilic addition

  • nucleophilic addition

Evaluation | Q 3. | Page 189

Reaction of acetone with one of the following reagents involves nucleophilic addition followed by elimination of water. The reagent is:

  • Grignard reagent

  • Sn/HCl

  • hydrazine in presence of slightly acidic solution

  • hydrocyanic acid

Evaluation | Q 4. | Page 189

In the following reaction,

\[\ce{HC ≡ CH ->[H2SO4][HgSO4] X}\]

Product ‘X’ will not give

  • Tollen’s test

  • Victor Meyer test

  • Iodoform test

  • Fehling solution test

Evaluation | Q 5. | Page 189

\[\ce{CH2 = CH2 ->[i) O3][ii) Zn/H2O] X ->[NH3] Y}\] ‘Y’ is:

  • Formaldehyde

  • di acetone ammonia

  • hexamethylene tetraamine

  • oxime

Evaluation | Q 6. | Page 189

Predict the product Z in the following series of reactions.

\[\ce{Ethanoic acid ->[PCl5] X ->[C6H6][Anhydrous AlCl3] Y ->[i) CH3MgBr][H3O^+] Z}\]

  • (CH3)2C(OH)C6H5

  • CH3CH(OH)C6H5

  • CH3CH(OH)CH2 – CH3

Evaluation | Q 7. | Page 189

Assertion: 2, 2-dimethyl propanoic acid does not give HVZ reaction.

Reason: 2-2, dimethyl propanoic acid does not have α-hydrogen atom.

  • if both assertion and reason are true and reason is the correct explanation of assertion.

  • if both assertion and reason are true but reason is not the correct explanation of assertion.

  • assertion is true but reason is false.

  • both assertion and reason are false.

Evaluation | Q 8. | Page 190

Which of the following represents the correct order of acidity in the given compounds.

  • FCH2COOH > CH3COOH > BrCH2COOH > ClCH2COOH

  • FCH2COOH > ClCH2COOH > BrCH2COOH > CH3COOH

  • CH3COOH > ClCH2COOH > FCH2COOH > Br-CH2COOH

  • ClCH2COOH > CH3COOH > BrCH2COOH > ICH2COOH

Evaluation | Q 9. | Page 190

\[\ce{Benzoic acid ->[i) NH3][ii) \Delta] A ->[NaOBr] B ->[NaNO2/HCl] C}\] ‘C’ is:

  • anilinium chloride

  • O-nitro aniline

  • benzene diazonium chloride

  • m-nitro benzoic acid

Evaluation | Q 10. | Page 190

\[\ce{Ethanoic acid ->[P/Br2] 2-bromoethanoic acid}\]. This reaction is called ____________.

  • Finkelstein reaction

  • Haloform reaction

  • Hell-Volhard-Zelinsky reaction

  • None of these

Evaluation | Q 11. | Page 190

\[\ce{CH3Br ->[KNC] (A) ->[H3O^+] (B) ->[PCl5] (C)}\] product (C) is:

  • acetyl chloride

  • chloro acetic acid

  • α-chlorocyano ethanoic acid

  • none of these

Evaluation | Q 12. | Page 190

Which one of the following reduces tollens reagent.

  • formic acid

  • acetic acid

  • benzophenone

  • none of these

Evaluation | Q 13. | Page 190

‘B’ is:

Evaluation | Q 14. | Page 190

The IUPAC name of

  • but-3-enoic acid

  • but-1-ene-4-oic acid

  • but-2-ene-1-oic acid

  • but-3-ene-1-oic acid

Evaluation | Q 15. | Page 191

Identify the product formed in the reaction.

Evaluation | Q 16. | Page 191

In which case, chiral carbon is not generated by reaction with HCN.

Evaluation | Q 17. | Page 191

Assertion: p-N, N-dimethyl amino benzaldehyde undergoes benzoin condensation

Reason: The aldehydic (−CHO) group is meta directing.

  • if both assertion and reason are true and reason is the correct explanation of assertion.

  • if both assertion and reason are true but reason is not the correct explanation of assertion.

  • assertion is true but reason is false.

  • both assertion and reason are false.

Evaluation | Q 18. | Page 191

Which one of the following reaction is an example of disproportionation reaction.

  • Aldol condensation

  • Cannizaro reaction

  • Benzoin condensation

  • None of these

Evaluation | Q 19. | Page 191

Which one of the following undergoes reaction with 50% sodium hydroxide solution to give the corresponding alcohol and acid.

  • Phenylmethanal

  • ethanal

  • ethanol

  • methanol

Evaluation | Q 20. | Page 192

The reagent used to distinguish between acetaldehyde and benzaldehyde is ____________.

  • Tollens reagent

  • Fehling’s solution

  • 2, 4-dinitrophenyl hydrazine

  • semicarbazide

Evaluation | Q 21. | Page 192

Phenyl methanal is reacted with concentrated NaOH to give two products X and Y. X reacts with metallic sodium to liberate hydrogen X and Y are ____________.

  • sodium benzoate and phenol

  • sodium benzoate and phenyl methanol

  • phenyl methanol and sodium benzoate

  • none of these

Evaluation | Q 22. | Page 192

In which of the following reactions new carbon-carbon bond is not formed?

  • Aldol condensation

  • Friedel craft reaction

  • Kolbe’s reaction

  • Wolf kishner reduction

Evaluation | Q 23. | Page 192

An alkene “A” on reaction with O3 and Zn – H2O gives propanone and ethanol in equimolar ratio. Addition of HCl to alkene “A” gives “B” as the major product. The structure of product “B” is

  • \[\begin{array}{cc}
    \phantom{....................}\ce{CH3}\\
    \phantom{.................}|\\
    \ce{Cl - CH2 - CH2 - CH}\\
    \phantom{.................}|\\
    \phantom{....................}\ce{CH3}
    \end{array}\]

  • \[\begin{array}{cc}
    \phantom{..........}\ce{CH2Cl}\\
    \phantom{.....}|\\
    \ce{H3C - CH2 - CH - CH3}
    \end{array}\]

  • \[\begin{array}{cc}
    \phantom{.........}\ce{CH3}\\
    \phantom{.......}|\\
    \ce{H3C - CH2 - C - CH3}\\
    \phantom{.......}|\\
    \phantom{........}\ce{Cl}
    \end{array}\]

  • \[\begin{array}{cc}
    \phantom{..............}\ce{CH3}\\
    \phantom{............}|\\
    \ce{H3C - CH - CH}\\
    \phantom{............}|\\
    \phantom{............}\ce{Cl}
    \end{array}\]

Evaluation | Q 24. | Page 192

Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their ____________.

  • more extensive association of carboxylic acid via van der Waals force of attraction

  • formation of carboxylate ion

  • formation of intramolecular H-bonding

  • formation of intermolecular H-bonding

Short Answer Questions:

Evaluation | Q 1. (a) | Page 192

How is propanoic acid is prepared to start from alcohol?

Evaluation | Q 1. (b) | Page 192

How is propanoic acid is prepared to start from an alkyl halide?

Evaluation | Q 1. (c) | Page 192

How is propanoic acid is prepared to start from an alkene?

Evaluation | Q 2. | Page 192

A Compound (A) with molecular formula C2H3N on acid hydrolysis gives (B) which reacts with thionyl chloride to give compound (C). Benzene reacts with compound (C) in presence of anhydrous AlCl3 to give compound (D). Compound (D) on reduction with Zn/Hg and Conc. HCl gives (E). Identify (A), (B), (C), (D) and (E). Write the equations.

Evaluation | Q 3. | Page 192

Identify X and Y.

\[\ce{CH3COCH2CH2COOC2H5 ->[CH3MgBr] X ->[H3O^+] Y}\]

Evaluation | Q 4. | Page 193

Identify A, B and C.

Evaluation | Q 5. | Page 193

Identify A, B, C and D.

\[\ce{ethanoic acid ->[SOCl2] A ->[Pd/BaSO4] B ->[NaOH] C ->[][\Delta] D}\]

Evaluation | Q 6. | Page 193

An alkene (A) on ozonolysis gives propanone and aldehyde (B). When (B) is oxidised (C) is obtained. (C) is treated with Br2/P gives (D) which on hydrolysis gives (E). When propanone is treated with HCN followed by hydrolysis gives (E). Identify A, B, C, D and E.

Evaluation | Q 7. (i) | Page 193

How will you convert benzaldehyde into the following compound?

Benzophenone

Evaluation | Q 7. (ii) | Page 193

How will you convert benzaldehyde into the following compound?

Benzoic acid

Evaluation | Q 7. (iii) | Page 193

How will you convert benzaldehyde into the following compound?

α-hydroxy phenyl acetic acid

Evaluation | Q 8. (i) | Page 193

What is the action of HCN on propanone?

Evaluation | Q 8. (ii) | Page 193

What is the action of HCN on 2, 4-dichlorobenzaldehyde?

Evaluation | Q 8. (iii) | Page 193

What is the action of HCN on ethanal?

Evaluation | Q 9. | Page 193

A carbonyl compound A having molecular formula C5H10O forms crystalline precipitate with sodium bisulphate and gives positive iodoform test. A does not reduce Fehling's solution. Identify A.

Evaluation | Q 10. | Page 193

Write the structure of the major product of the aldol condensation of benzaldehyde with acetone.

Evaluation | Q 11. (a) | Page 193

How is the following conversion effected propanal into butanone?

Evaluation | Q 11. (b) | Page 193

How is the following conversion effected Hex-3-yne into hexan-3-one?

Evaluation | Q 11. (c) | Page 193

How is the following conversion effected phenyl methanal into benzoic acid?

Evaluation | Q 11. (d) | Page 193

How is the following conversion effected phenyl methanal into benzoin?

Evaluation | Q 12. | Page 193

Complete the following reaction.

\[\begin{array}{cc}
\ce{CH3 - CH2 - CH2 - C - CH3 ->[HO - CH2 - CH2 - CH2 - OH][dry HCl] ?}\\
||\phantom{.........}\\
\ce{O}\phantom{.........}
\end{array}\]

Evaluation | Q 13. | Page 193

Identify A, B and C.

Evaluation | Q 14. | Page 194

Oxidation of ketones involves carbon-carbon bond cleavage. Name the product(s) is/are formed on oxidising 2, 5-dimethyl hexan-3-one using a strong oxidising agent.

Evaluation | Q 15. i. | Page 194

How will you prepare acetic anhydride from acetic acid?

Evaluation | Q 15. ii. | Page 194

How will you prepare ethyl acetate from methyl acetate?

Evaluation | Q 15. iii. | Page 194

How will you prepare acetamide from methyl cyanide?

Evaluation | Q 15. iv. | Page 194

How will you prepare lactic acid from ethanol?

Evaluation | Q 15. v. | Page 194

How will you prepare acetophenone from acetyl chloride?

Evaluation | Q 15. vi. | Page 194

How will you prepare ethane from sodium acetate?

Evaluation | Q 15. vii. | Page 194

How will you prepare benzoic acid from toluene?

Evaluation | Q 15. viii. | Page 194

How will you prepare malachite green from benzaldehyde?

Evaluation | Q 15. ix. | Page 194

How will you prepare cinnamic acid from benzaldehyde?

Evaluation | Q 15. x. | Page 194

How will you prepare acetaldehyde from ethyne?

Solutions for 12: Carbonyl Compounds and Carboxylic Acids

Evaluation
Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 12 TN Board chapter 12 - Carbonyl Compounds and Carboxylic Acids - Shaalaa.com

Samacheer Kalvi solutions for Chemistry - Volume 1 and 2 [English] Class 12 TN Board chapter 12 - Carbonyl Compounds and Carboxylic Acids

Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Chemistry - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Chemistry - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education 12 (Carbonyl Compounds and Carboxylic Acids) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Samacheer Kalvi textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Chemistry - Volume 1 and 2 [English] Class 12 TN Board chapter 12 Carbonyl Compounds and Carboxylic Acids are Nomenclature of Aldehydes and Ketones, Structure of Carbonyl Group, General Methods of Preparation of Aldehydes and Ketones, Physical Properties of Aldehydes and Ketones, Chemical Properties of Aldehydes and Ketones, Test for Aldehydes, Uses of Carboxylic Acids and Its Derivatives, Uses of Aldehydes and Ketones, IUPAC Nomenclature of Carboxylic Acids, Structure of the Carboxyl group, Methods of Preparation of Carboxylic Acids, Physical Properties of Carboxylic Acids, Chemical Properties of Carboxylic Acids, Acidity of Carboxylic Acids, Functional Derivatives of Carboxylic Acids.

Using Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 12 TN Board solutions Carbonyl Compounds and Carboxylic Acids exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Chemistry - Volume 1 and 2 [English] Class 12 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.

Get the free view of Chapter 12, Carbonyl Compounds and Carboxylic Acids Chemistry - Volume 1 and 2 [English] Class 12 TN Board additional questions for Mathematics Chemistry - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.

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