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How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated? - Mathematics

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प्रश्न

How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

योग

उत्तर

3-digit numbers have to be formed using the digits 1 to 9.

Here, the order of the digits matters.

Therefore, there will be as many 3-digit numbers as there are permutations of 9 different digits taken 3 at a time.

Therefore, required number of 3-digit numbers

 = 9P3 = `(9!)/((9 - 3)!) = (9!)/(6!)`

= `(9 xx 8 xx 7 xx 6!)/(6!)`

= 9 x 8 x 7 = 504

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अध्याय 7: Permutations and Combinations - Exercise 7.3 [पृष्ठ १४८]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise 7.3 | Q 1 | पृष्ठ १४८

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