हिंदी

In how many ways can 5 children be arranged in a line such that two particular children of them are never together. - Mathematics

Advertisements
Advertisements

प्रश्न

In how many ways can 5 children be arranged in a line such that two particular children of them are never together.

योग

उत्तर

Among the 5! = 120 permutations of 5 children.

There are 48 in which two children are together.

In the remaining 120 – 48 = 72 permutations

Two particular children are never together.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Permutations and Combinations - Solved Examples [पृष्ठ ११७]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Solved Examples | Q 4.(ii) | पृष्ठ ११७

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

How many 4-digit numbers are there with no digit repeated?


In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S.


How many three digit numbers can be formed by using the digits 0, 1, 3, 5, 7 while each digit may be repeated any number of times?


Find the number of ways in which one can post 5 letters in 7 letter boxes ?


Evaluate each of the following:

P(6, 4)


In how many ways can 4 letters be posted in 5 letter boxes?


Write the number of ways in which 7 men and 7 women can sit on a round table such that no two women sit together ?


Write the number of words that can be formed out of the letters of the word 'COMMITTEE' ?


Write the number of ways in which 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys ?


Write the number of numbers that can be formed using all for digits 1, 2, 3, 4 ?


The number of words that can be formed out of the letters of the word "ARTICLE" so that vowels occupy even places is


The number of different signals which can be given from 6 flags of different colours taking one or more at a time, is


The number of arrangements of the word "DELHI" in which E precedes I is


The number of ways in which the letters of the word 'CONSTANT' can be arranged without changing the relative positions of the vowels and consonants is


How many numbers lesser than 1000 can be formed using the digits 5, 6, 7, 8, and 9 if no digit is repeated?


How many 6-digit telephone numbers can be constructed with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if each numbers starts with 35 and no digit appear more than once?


  1. In how many ways can 8 identical beads be strung on a necklace?
  2. In how many ways can 8 boys form a ring?

If n is a positive integer, then the number of terms in the expansion of (x + a)n is:


For all n > 0, nC1 + nC2 + nC3 + …… + nCn is equal to:


Suppose 8 people enter an event in a swimming meet. In how many ways could the gold, silver and bronze prizes be awarded?


A student appears in an objective test which contain 5 multiple choice questions. Each question has four choices out of which one correct answer.

How will the answer change if each question may have more than one correct answers?


In how many ways 4 mathematics books, 3 physics books, 2 chemistry books and 1 biology book can be arranged on a shelf so that all books of the same subjects are together


A coin is tossed 8 times, how many different sequences containing six heads and two tails are possible?


How many strings are there using the letters of the word INTERMEDIATE, if all the vowels are together


Each of the digits 1, 1, 2, 3, 3 and 4 is written on a separate card. The six cards are then laid out in a row to form a 6-digit number. How many of these 6-digit numbers are divisible by 4?


Choose the correct alternative:
If Pr stands for rPr then the sum of the series 1 + P1 + 2P2 + 3P3 + · · · + nPn is


There are 10 persons named P1, P2, P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.


The number of 5-digit telephone numbers having atleast one of their digits repeated is ______.


In the permutations of n things, r taken together, the number of permutations in which m particular things occur together is `""^(n - m)"P"_(r - m) xx ""^r"P"_m`.


Let b1, b2, b3, b4 be a 4-element permutation with bi ∈ {1, 2, 3, .......,100} for 1 ≤ i ≤ 4 and bi ≠ bj for i ≠ j, such that either b1, b2, b3 are consecutive integers or b2, b3, b4 are consecutive integers. Then the number of such permutations b1, b2, b3, b4 is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×