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How many different selections of 5 books can be made from 12 different books if, Two particular books are always selected? - Mathematics

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प्रश्न

How many different selections of 5 books can be made from 12 different books if, Two particular books are always selected?

योग

उत्तर

Total number of books = 12

Number of books to be selected = 5

Given Two books are always selected.

Remaining number of books to be selected = 3

The number of ways of selecting the remaining 3 books from the remaining 10 books = 10C

= `(10!)/(3! xx (10 - 3)!)`

= `(10!)/(3! xx 7!)`

= `(10 xx 9 xx 8 xx 7!)/(3! xx 7!)`

= `(10 xx 9 xx 8)/(3!)`

= `(10 xx 9 xx 8)/(3 xx 2 xx 1)`

= 5 × 3 × 8

= 120 ways

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Combinations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.3 [पृष्ठ १८७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.3 | Q 13. (i) | पृष्ठ १८७

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