Advertisements
Advertisements
प्रश्न
How many photons per second emanate from a 50 mW laser of 640 nm?
उत्तर
P = 50 mW
λ = 640 nm
h = 6.6 × 10−34 Js
c = 3 × 108 ms−1
Number of photons emanate per second np = `"P"/"E" = ("P"λ)/"hc"`
= `(50 xx 10^3 xx 640 xx 10^-9)/(6.6 xx 10^-34 xx 3 xx 10^8)`
= 1616.16 × 10−6
np = 1.61 × 1017 s−1
APPEARS IN
संबंधित प्रश्न
When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is `"V"/4`. The threshold wavelength for the metallic surface is
A light of wavelength 500 nm is incident on a sensitive metal plate of photoelectric work function 1.235 eV. The kinetic energy of the photoelectrons emitted is (Take h = 6.6 × 10–34 Js)
Photons of wavelength λ are incident on a metal. The most energetic electrons ejected from the metal are bent into a circular arc of radius R by a perpendicular magnetic field having magnitude B. The work function of the metal is
How does photocurrent vary with the intensity of the incident light?
What is a photocell?
Define stopping potential.
Mention the two features of x-ray spectra, not explained by classical electromagnetic theory.
How many photons of frequency 1014 Hz will make up 19.86 J of energy?
When a light of frequency 9 × 1014 Hz is incident on a metal surface, photoelectrons are emitted with a maximum speed of 8 × 105 ms−1. Determine the threshold frequency of the surface.
UV light of wavelength 1800 Å is incident on a lithium surface whose threshold wavelength is 4965 Å. Determine the maximum energy of the electron emitted.