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प्रश्न
How much calcium oxide is obtained by heating 82 g of calcium nitrate? Also, find the volume of NO2 evolved:
\[\ce{2Ca(NO3)2 ->2CaO + 4NO2 + O2}\]
उत्तर
\[\ce{2Ca(NO3)2 ->2CaO + 4NO2 + O2}\]
Molecular Weight of 2Ca(NO3)2 = 2(40 + 28 + 96) = 328 g
Molecular weight of CaO = 2(40 + 16) = 112 g
328 g of Ca(NO3)2 forms 112 g of CaO
82 g of Ca(NO3)2 forms `112/328 xx 82` = 28 g
328 g of Ca(NO3)2 will evolved 4× 22.4 l of NO2
82 g of Ca(NO3)2 will evolve `(4 xx 22.4)/328 xx 82` = 22.4 l
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