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प्रश्न
60 cm3 of oxygen was added to 24 cm3 of carbon monoxide and mixture ignited. Calculate the volume of oxygen used up.
उत्तर १
\[\ce{2CO + O2 → 2CO2}\]
2 V 1 V 2 V
2 V CO requires oxygen = 1 V
so, 24 cm3 CO will require = 24/2 =12 cm3
उत्तर २
\[\ce{2CO + O2 → 2CO2}\]
According to this equation,
Volume of oxygen used for 44800 cm3 of carbon monoxide = 22400 cm3
∴ Volume of oxygen used up for 24 cm3 of carbon monoxide = `22400/44800 xx 24` cm3
= 12 cm3
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