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प्रश्न
What is the volume occupied by 16g of sulphur dioxide. gas at STP?
उत्तर
Volume occupied by 16g of sulphur dioxide.
64g of sulphur dioxide at STP occupies volume of = 22.4 L
16g of sulphur dioxide at STP occupies volume of = 22.4 x 16/64 = 5.6 L
Hence, 16g of sulphur dioxide will occupy a volume of 5.6 L
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संबंधित प्रश्न
Copper sulphate solution reacts with sodium hydroxide solution to form a precipitate of copper hydroxide according to the equation :
2NaOH + CuSO4 → Na2SO4 + Cu (OH)2 ↓
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[H = 1, O = 16, Na = 23, S = 32, Cu = 64]
(ii) What is the colour of the precipitate formed?
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2H2S + 3O2 → 2H2O + 2SO2
The equations given below relate to the manufacture of sodium carbonate (Molecular weight of Na2CO3 = 106).
- \[\ce{NaCl + NH3 + CO2 + H2O -> NaHCO3 + NH4Cl}\]
- \[\ce{2NaHCO3 -> Na2CO3 + H2O + CO2}\]
Equations (1) and (2) are based on the production of 21.2 g of sodium carbonate.
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\[\ce{2H2S + 3O2 -> 2H2O + 2SO2}\]
Calculate the volume of hydrogen sulphide at STP. Also, calculate the volume of oxygen required at STP which will complete the combustion of hydrogen sulphide determined in litres.
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- The pressure inside the tank is 800 mm of Hg.
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When the cylinder is filled, the pressure gauge reads 400 mm of Hg and the temperature is 270 K. Find the number of cylinders required to fill the gas.
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