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प्रश्न
Identify the substances that are oxidised and the substances that are reduced in the following reaction.
\[\ce{CuO(s) + H2(g) -> Cu(s) + H2O (l)}\]
उत्तर
In the given reaction hydrogen is being oxidised and Cu is being reduced.
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संबंधित प्रश्न
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Define corrosion.
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MnO2 + 4HCl → MnCl2 + 2H2O + Cl2
(i) name the substance oxidised.
(ii) name the oxidising agent.
(iii) name the substance reduced.
(iv) name the reducing agent.
Is oxidation an exothermic or an endothermic reaction?
Explain reduction in terms of gain or loss of oxygen with one example.
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(a) oxidation
(b) dehydration
(c) reduction
(d) dehydrogenation
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Cl2 + 2Br- → Br2 + 2Cl-
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Name:
a solid that is an oxidizing agent.
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CuSO4 + Fe → Cu + FeSO4
Which option in the given table correctly represents the substance oxidized and the reducing agent?
OPTION | Substance Oxidized | Reducing Agent |
A | Fe | Fe |
B | Fe | FeSO4 |
C | Cu | Fe |
D | CuSO4 | Fe |
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- Write the equation.
- What type of reaction is it?
- Complete the blanks:
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State the change in colour observed in following case mentioning the reason:
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