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If 148101B095 is divisible by 33, find the value of B. - Mathematics

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प्रश्न

If 148101B095 is divisible by 33, find the value of B.

योग

उत्तर

Given that the number 148101S095 is divisible by 33, therefore it is also divisible by 3 and 11 both.

Now, the number is divisible by 3, its sum of digits is a multiple of 3. i.e. 1 + 4 + 8 + 1 + 0 + 1 + B + 0 + 9 + 5 is a multiple of 3.

29 + B = 0, 3, 6, 9, ...

⇒ B = 1, 4, 7  ...(i)

Also, given number is divisible by 11, therefore

(1 + 8 + 0 + B + 9) – (4 + 1 + 1 + 0 + 5) = 0, 11, 22, ...

⇒ (18 + B) – 11 = 0, 11, 22

B + 7 = 0, 11, 22

⇒ B + 7 = 11

⇒ B = 4  ...(ii)

From equations (i) and (ii), we have

B = 4

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अध्याय 13: Playing With Numbers - Exercise [पृष्ठ ४१३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 13 Playing With Numbers
Exercise | Q 72. | पृष्ठ ४१३

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