Advertisements
Advertisements
Question
If 148101B095 is divisible by 33, find the value of B.
Solution
Given that the number 148101S095 is divisible by 33, therefore it is also divisible by 3 and 11 both.
Now, the number is divisible by 3, its sum of digits is a multiple of 3. i.e. 1 + 4 + 8 + 1 + 0 + 1 + B + 0 + 9 + 5 is a multiple of 3.
29 + B = 0, 3, 6, 9, ...
⇒ B = 1, 4, 7 ...(i)
Also, given number is divisible by 11, therefore
(1 + 8 + 0 + B + 9) – (4 + 1 + 1 + 0 + 5) = 0, 11, 22, ...
⇒ (18 + B) – 11 = 0, 11, 22
B + 7 = 0, 11, 22
⇒ B + 7 = 11
⇒ B = 4 ...(ii)
From equations (i) and (ii), we have
B = 4
APPEARS IN
RELATED QUESTIONS
Which of the following statement is true?
If a number is divisible by 4, it must be divisible by 8.
Which of the following statement is true?
A number is divisible by 18, if it is divisible by both 3 and 6.
Use the same rule to fill the hexagons below.
Now you also make your own magic hexagons.
Fill in the blank space in the same way.
20 × 3 is a multiple of 3 if the digit × is ______ or ______ or ______.
If 
then B = ______.
If a 3-digit number abc is divisible by 11, then ______ is either 0 or multiple of 11.
A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.
If 56 × 32y is divisible by 18, find the least value of y.
Fill in the blank space in the same way.
