हिंदी

If 200 mL of ethylene gas and 200 mL of HCl gas are allowed to react at 2 atmosphere pressure as per given reaction, CX2HX4(g)+HClX(g)⟶CX2HX5ClX(g) -

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प्रश्न

If 200 mL of ethylene gas and 200 mL of HCl gas are allowed to react at 2 atmosphere pressure as per given reaction,

\[\ce{C2H_{4(g)} + HCl_{(g)} -> C2H5Cl_{(g)}}\]

Calculate pressure volume work in Joule.

विकल्प

  • 20.26 J

  • 54.40 J

  • 40.52 J

  • 26.20 J

MCQ

उत्तर

40.52 J

Explanation:

\[\ce{C2H_{4(g)} + HCl_{(g)} -> C2H5Cl_{(g)}}\]

200 mL     200 mL        200 mL

∴ ΔV = Volume of Product (V2) - Volume of reactant (V1)

= 200 - 400 

= - 200 mL = - 0.2 L

∴ W = - P · ΔV

= - 2 × (- 0.2) = 0.4 L atm

= 0.4 × 101.325

= 40.53 J

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Expression for Pressure-volume (PV) Work
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