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Question
If 200 mL of ethylene gas and 200 mL of HCl gas are allowed to react at 2 atmosphere pressure as per given reaction,
\[\ce{C2H_{4(g)} + HCl_{(g)} -> C2H5Cl_{(g)}}\]
Calculate pressure volume work in Joule.
Options
20.26 J
54.40 J
40.52 J
26.20 J
MCQ
Solution
40.52 J
Explanation:
\[\ce{C2H_{4(g)} + HCl_{(g)} -> C2H5Cl_{(g)}}\]
200 mL 200 mL 200 mL
∴ ΔV = Volume of Product (V2) - Volume of reactant (V1)
= 200 - 400
= - 200 mL = - 0.2 L
∴ W = - P · ΔV
= - 2 × (- 0.2) = 0.4 L atm
= 0.4 × 101.325
= 40.53 J
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Expression for Pressure-volume (PV) Work
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