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प्रश्न
If a = 23 ✕ 3, b = 2 ✕ 3 ✕ 5, c = 3n ✕ 5 and LCM (a, b, c) = 23 ✕ 32 ✕ 5, then n =
विकल्प
1
2
3
4
उत्तर
LCM (a,b,c)= `2^2xx3^2xx5` ……(I)
We have to find the value for n
Also
`a= 2^3xx3`
`b=2xx3xx5`
`c=3^nxx5`
We know that the while evaluating LCM, we take greater exponent of the prime numbers in the factorization of the number.
Therefore, by applying this rule and taking ` n ≥ 1` we get the LCM as
LCM `(a,b,c)= 2^1xx3^nxx5` ……(II)
On comparing (I) and (II) sides, we get:
`2^3xx3^2xx5=2^3xx3^nxx5`
n=2
Hence the correct choice is (b).
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