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प्रश्न
If `"a"^2+ 1/"a"^2=23`, find : `"a" +1/"a"`
योग
उत्तर
`("a"+1/"a")^2="a"^2+1/"a"^2+2`
`⇒("a"+1/"a")^2=23+2`
`⇒("a"+1/"a")^2=25`
`⇒"a"+1/"a"=sqrt25`
`⇒"a"+1/"a"=±5`
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