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प्रश्न
If `"a"^2+ 1/"a"^2=11`, find : `"a" -1/"a"`
योग
उत्तर
`("a"-1/"a")^2="a"^2+1/"a"^2-2`
`⇒("a"-1/"a")^2=11-2`
`⇒("a"-1/"a")^2=9`
`⇒"a"-1/"a"=sqrt9`
`⇒"a"-1/"a"=±3`
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