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If a, b and c are in continued proportion, prove that a2+b2+c2(a+b+c)2 =a-b+ca+b+c - Mathematics

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प्रश्न

If a, b and c are in continued proportion, prove that `(a^2 + b^2 + c^2)/(a + b + c)^2  = (a - b + c)/(a + b + c)`

योग

उत्तर

Given, a, b and c are in continued proportion.

Therefore,

`a/b = b/c`

ac = b2

L.H.S = `(a^2 + b^2 + c^2)/(a + b + c)^2`

= `(a^2 + b^2 + c^2 + 2ab + 2bc + 2ac - (2ab + 2bc + 2ac))/((a + b + c)^2)`

= `((a + b + c)^2 - 2(ab + bc + b^2))/((a + b + c)^2)`

= `((a + b + c)^2 - 2b(a + c + b))/((a + b + c)^2)`

= `((a + b + c)(a + b + c - 2b))/((a + b + c)^2)`

= `(a - b + c)/(a + b + c)`

Hence proved.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Ratio and Proportion (Including Properties and Uses) - Exercise 7 (C) [पृष्ठ १०१]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 7 Ratio and Proportion (Including Properties and Uses)
Exercise 7 (C) | Q 10.2 | पृष्ठ १०१
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