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If xa=yb=zc, prove that x3a2+y3b2+z3c2=(x+y+z)3(a+b+c)2 - Mathematics

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प्रश्न

If `x/a = y/b = z/c`, prove that `x^3/a^2 + y^3/b^2 + z^3/c^2 = (x+ y+ z)^3/(a + b+ c)^2`

योग

उत्तर

`x/a = y/b = z/c`
∴ x = ak, y = bk, z = ck

L.H.S. = `x^3/a^2 + y^3/b^2 + z^3/c^2`

= `(a^3k^3)/a^2 + (b^3k^3)/(b^2) + (c^3k^3)/c^2`
= ak3 + bk3 + ck3
= k3(a + b + c)

R.H.S. = `(x + y + z)^3/(a + b + c)^2`

= `(ak + bk + ck)^3/(a + b + c)^2`

= `(k^3(a + b + c)^3)/((a + b + c)`
= k3(a + b + c)
Hence L.H.S. = R.H.S.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Ratio and Proportion - Exercise 7.2

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एमएल अग्रवाल Understanding ICSE Mathematics [English] Class 10
अध्याय 7 Ratio and Proportion
Exercise 7.2 | Q 16.1
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