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If a, b, c and d are in proportion, prove that: (ma + nb) : b = (mc + nd) : d - Mathematics

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प्रश्न

If a, b, c and d are in proportion, prove that: (ma + nb) : b = (mc + nd) : d

योग

उत्तर

∵ a, b, c, d are in proportion
`a/b = c/d` = k(say)
a = bk, c = dk.
(ma + nb) : b = (mc + nd) : d

⇒ `"ma + nb"/b = "mc + nd"/d`

L.H.S. = `"mbk + nb"/b`

= `(b("mk + n"))/b`
= mk + n
R.H.S. = `"mc + nd"/d`

= `"mdk + nd"/d`

= `(d("mk + n"))/d`
= mk + n.
∴ L.H.S. = R.H.S.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Ratio and Proportion - Exercise 7.2

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एमएल अग्रवाल Understanding ICSE Mathematics [English] Class 10
अध्याय 7 Ratio and Proportion
Exercise 7.2 | Q 19.2
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