Advertisements
Advertisements
प्रश्न
If the mean of the following data is 15, find p.
x | 5 | 10 | 15 | 20 | 25 |
f | 6 | P | 6 | 10 | 5 |
उत्तर
x | f | fx |
5 | 6 | 30 |
10 | P | 10P |
15 | 6 | 90 |
20 | 10 | 200 |
25 | 5 | 125 |
N = P + 27 | `sum` fx = 10P + 445 |
Given
⇒ Mean = 15
`rArr(sumfx)/N=15`
`rArr(10P+445)/(P+27)`
⇒ 10P + 445 = 15(P + 27)
⇒ 10P + 445 = 15P + 405
⇒ 15P - 10P = 445 - 405
⇒ 5P = 40
`rArrp=40/5`
⇒ P = 8
APPEARS IN
संबंधित प्रश्न
Find the value of p, if the mean of the following distribution is 20.
x | 15 | 17 | 19 | 20+P | 23 |
f | 2 | 3 | 4 | 5P | 6 |
The mean of following frequency distribution is 54. Find the value of p.
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
Frequency | 7 | p | 10 | 9 | 13 |
If the mean of 6, 7, x, 8, y, 14 is 9, then ______.
Find the mean of the following distribution:
Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Frequency | 10 | 6 | 8 | 12 | 5 |
While computing mean of grouped data, we assume that the frequencies are ______.
In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, ui = ______.
If the mean of 9, 8, 10, x, 14 is 11, find the value of x.
Find the mean of the following frequency distribution:
Class | 1 – 5 | 5 – 9 | 9 – 13 | 13 – 17 |
Frequency | 4 | 8 | 7 | 6 |
The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution by using the short cut method.
Marks | Number of Students (f) |
0 – 10 | 3 |
10 – 20 | 8 |
20 – 30 | 14 |
30 – 40 | 9 |
40 – 50 | 4 |
50 – 60 | 2 |
Using step-deviation method, find mean for the following frequency distribution:
Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
Frequency | 3 | 4 | 7 | 6 | 8 | 2 |