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प्रश्न
In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, ui = ______.
विकल्प
`(x_i + a)/h`
`h(x_i - a)`
`(x_i - a)/h`
`(a - x_i)/h`
उत्तर
In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, ui = `underlinebb((x_i - a)/h)`.
Explanation:
According to the question,
`barx = a + h((sumf_iu_i)/(sumf_i))`
Above formula is a step deviation formula.
In the above formula,
xi is data values,
a is assumed mean,
h is class size,
When class size is same we simplify the calculations of the mean by computing the coded mean of u1, u2, u3 …..,
Where ui = `(x_i - a)/h`
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संबंधित प्रश्न
Find the mean of the following data:-
| x | 19 | 21 | 23 | 25 | 27 | 29 | 31 |
| f | 13 | 15 | 16 | 18 | 16 | 15 | 13 |
Find the value of p for the following distribution whose mean is 16.6
| x | 8 | 12 | 15 | P | 20 | 25 | 30 |
| f | 12 | 16 | 20 | 24 | 16 | 8 | 4 |
Find the value of p, if the mean of the following distribution is 20.
| x | 15 | 17 | 19 | 20+P | 23 |
| f | 2 | 3 | 4 | 5P | 6 |
Find the mean of the following data, using step-deviation method:
| Class | 5 – 15 | 15-20 | 20-35 | 35-45 | 45-55 | 55-65 | 65-75 |
| Frequency | 6 | 10 | 16 | 15 | 24 | 8 | 7 |
Find the mean of the following frequency distribution table using a suitable method:
| Class | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 - 70 |
| Frequency | 25 | 40 | 42 | 33 | 10 |
Find the correct answer from the alternatives given.
The formula to find mean from a grouped frequency table is \[X = A + \frac{\sum f_i u_i}{\sum f_i} \times hg\] .
If the mean of the following frequency distribution is 18, find the missing frequency.
| Class interval | 11 – 13 | 13 – 15 | 15 – 17 | 17 – 19 | 19 – 21 | 21 – 23 | 23 – 25 |
| Frequency | 3 | 6 | 9 | 13 | f | 5 | 4 |
If the mean of the following distribution is 2.6, then the value of y is:
| Variable (x) | 1 | 2 | 3 | 4 | 5 |
| Frequency | 4 | 5 | y | 1 | 2 |
The mean of the following distribution is 6. Find the value at P:
| x | 2 | 4 | 6 | 10 | P + 5 |
| f | 3 | 2 | 3 | 1 | 2 |
Given that the mean of the following frequency distribution is 30, find the missing frequency ‘f’.
| Class Interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 |
| Frequency | 4 | 6 | 10 | f | 6 | 4 |
