Advertisements
Advertisements
Question
In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, ui = ______.
Options
`(x_i + a)/h`
`h(x_i - a)`
`(x_i - a)/h`
`(a - x_i)/h`
Solution
In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, ui = `underlinebb((x_i - a)/h)`.
Explanation:
According to the question,
`barx = a + h((sumf_iu_i)/(sumf_i))`
Above formula is a step deviation formula.
In the above formula,
xi is data values,
a is assumed mean,
h is class size,
When class size is same we simplify the calculations of the mean by computing the coded mean of u1, u2, u3 …..,
Where ui = `(x_i - a)/h`
APPEARS IN
RELATED QUESTIONS
If the mean of the following data is 15, find p.
| x | 5 | 10 | 15 | 20 | 25 |
| f | 6 | P | 6 | 10 | 5 |
Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.
| No. of heads per toss | No. of tosses |
| 0 | 38 |
| 1 | 144 |
| 2 | 342 |
| 3 | 287 |
| 4 | 164 |
| 5 | 25 |
| Total | 1000 |
The daily expenditure of 100 families are given below. Calculate `f_1` and `f_2` if the mean daily expenditure is ₹ 188.
|
Expenditure (in Rs) |
140-160 | 160-180 | 180-200 | 200-220 | 220-240 |
|
Number of families |
5 | 25 | `f_1` | `f_2` | 5 |
The weights of tea in 70 packets are shown in the following table:
| Weight | 200 – 201 |
201 – 202 |
202 – 203 |
203 – 204 |
204 – 205 |
205 – 206 |
| Number of packets | 13 | 27 | 18 | 10 | 1 | 1 |
Find the mean weight of packets using step deviation method.
The loans sanctioned by a bank for construction of farm ponds are shown in the following table. Find the mean of the loans.
|
Loan
(Thousand Rupees)
|
40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 | 80 - 90 |
| No. of farm ponds | 13 | 20 | 24 | 36 | 7 |
If the mean of frequency distribution is 8.1 and Σfixi = 132 + 5k, Σfi = 20, then k =?
In the formula
Find the mean of the following distribution:
| x | 4 | 6 | 9 | 10 | 15 |
| f | 5 | 10 | 10 | 7 | 8 |
Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is ______.
If the mean of 9, 8, 10, x, 14 is 11, find the value of x.
