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प्रश्न
If P = –(x – 2), Q = –2(y + 1) and R = –x + 2y, find a, when P + Q + R = ax.
उत्तर
Given, P = –(x – 2), Q = –2(y + 1) and R = –x + 2y
Also given, P + Q + R = ax
On putting the values of P, Q and R on LHS, we get
–(x – 2) + [–2(y + 1)] + (–x + 2y) = ax
⇒ –x + 2 + (–2y – 2) – x + 2y = ax
⇒ –x + 2 – 2y – 2 – x + 2y = ax
On combining the like terms,
–x – x – 2y + 2y + 2 – 2 = ax
⇒ –2x = ax
By comparing LHS and RHS, we get a = –2
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