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प्रश्न
If the separation between the slits in a Young's double slit experiment is increased, what happens to the fringe-width? If the separation is increased too much, will the fringe pattern remain detectable?
उत्तर
The fringe width in Young's double slit experiment depends on the separation of the slits.
\[\chi = \frac{\lambda D}{d}\]
where
\[\lambda =\text{ wavelength}\]
\[\chi =\text{ fringe width}\]
\[D =\text{ distance between slits and screen}\]
\[d =\text{ separation between slits}\]
On increasing d, fringe width decreases. If the separation is increased too much, the fringes will merge with each other and the fringe pattern won't be detectable.
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संबंधित प्रश्न
(i) In Young's double-slit experiment, deduce the condition for (a) constructive and (b) destructive interferences at a point on the screen. Draw a graph showing variation of intensity in the interference pattern against position 'x' on the screen.
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(A) equal width with same intensity
(B) unequal width with varying intensity
(C) equal intensity\
(D) equal width with varying intensity
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(a) The central fringe will be white.
(b) There will not be a completely dark fringe.
(c) The fringe next to the central will be red.
(d) The fringe next to the central will be violet.
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(ii) Fringe width, i.e. fringe separation.
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