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प्रश्न
If the demand function is D = `((p + 6)/(p − 3))`, find the elasticity of demand at p = 4.
उत्तर
Given, demand function is D = `((p + 6)/(p − 3))`
∴ `"dD"/"dp" = ((p − 3) "d"/"dp" (p + 6) − (p + 6) "d"/"dp" (p − 3))/(p − 3)^2`
∴ `"dD"/"dp" = ((p − 3)(1 + 0) − (p + 6)(1 − 0))/(p − 3)^2`
∴ `"dD"/"dp" = (cancelp − 3 − cancelp − 6)/(p − 3)^2`
∴ `"dD"/"dp" = (-9)/(p − 3)^2`
`eta = (−p)/"D". "dD"/"dp"`
∴ `eta = (− p)/(((p + 6)/cancel(p − 3))) . (− 9)/(p − 3)^cancel2`
∴ `eta = (9p)/((p + 6)(p - 3))`
Substituting p = 4, we get,
∴ `eta = (9 xx 4)/((4 + 6)(4 - 3))`
∴ `eta = 36/(10 × 1)`
∴ `eta = 36/10`
∴ η = 3.6
∴ η (elasticity of demand at p = 4) = 3.6.
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