Advertisements
Advertisements
प्रश्न
If x = `2/3` is a solution of the quadratic equation 7x2+mx - 3=0;
Find the value of m.
उत्तर
7x2+mx - 3=0
Given x = `2/3` is the solution of the given equation.
Put given value of x in the given equation
`7(2/3)^2 + "m"(2/3) - 3 = 0`
⇒ `28/9 + (2"m")/3` - 3 = 0
⇒ 28 + 6m - 27 = 0
⇒ 6m = -1
⇒ m = `(-1)/6`
APPEARS IN
संबंधित प्रश्न
Solve the following equation and give your answer correct to 3 significant figures:
5x2 – 3x – 4 = 0
Solve : x(x – 5) = 24
Without solving comment upon the nature of roots of each of the following equation:
2x2 + 8x + 9 = 0
Which of the following are quadratic equation in x?
`sqrt2x^2+7x+5sqrt2`
`9x^2-9(a+b)x+(2a^2+5ab+2b^2)=0`
Find the roots of the following quadratic equation:
`x^2-3sqrt5x+10=0`
Solve equation using factorisation method:
`9/2 x = 5 + x^2`
Find the value of x, if a + 7 = 0; b + 10 = 0 and 12x2 = ax – b.
Check whether the following are quadratic equations: `sqrt(3)x^2 - 2x + (3)/(5) = 0`
Solve the following equation by using formula :
10ax2 – 6x + 15ax – 9 = 0,a≠0