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प्रश्न
If x = 3, y = 2 and z = 1; find the value of xy + y2z – 4zx
योग
उत्तर
x = 3, y = 2, z = 1
xy + y2z – 4zx
= 3 × 2 + (2)2 × 1 − 4 × 1 × 3
= 6 + 4 − 12
= 10 − 12
= − 2
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