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प्रश्न
If x = 3, y = 2 and z = 1; find the value of y2 – x2 + 6z2
योग
उत्तर
x = 3, y = 2, z = 1
y2 – x2 + 6z2
= (2)2 − (3)2 + 6(1)2
= 4 – 9 + 6 × 1
= 4 – 9 + 6
= 10 – 9
= 1
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