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प्रश्न
If (x + a)(x + b)(x + c) = x3 + 14x2 + 59x + 70, find the value of `1/"a" + 1/"b" + 1/"c"`
उत्तर
(x + a)(x + b)(x + c) = x3 + 14x2 + 59x + 70
x3 + (a + b + c)x2 + (ab + bc + ac)x + abc = x3 + 14x2 + 59x + 70
a + b + c = 14, ab + bc + ac = 59, abc = 70
`1/"a" + 1/"b" + 1/"c" = ("bc" + "ac" + "ab")/"abc"`
= `59/70`
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