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प्रश्न
If (x + a)(x + b)(x + c) = x3 + 14x2 + 59x + 70, find the value of `"a"/"bc" + "b"/"ac" + "c"/"ab"`
उत्तर
(x + a)(x + b)(x + c) = x3 + 14x2 + 59x + 70
x3 + (a + b + c)x2 + (ab + bc + ac)x + abc = x3 + 14x2 + 59x + 70
a + b + c = 14, ab + bc + ac = 59, abc = 70
`"a"/"bc" + "b"/"ac" + "c"/"ab" = ("a"^2 + "b"^2 + "c"^2)/"abc"`
= `(("a" + "b" + "c")^2 - 2("ab" + "bc" + "ac"))/"abc"`
= `(14^2 - 2(59))/70`
= `(196 - 118)/70`
= `78/70`
= `39/35`
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