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प्रश्न
If x sin θ = y cos θ = `(2z tan θ)/(1 - tan^2 θ)`, then 4z2(x2 + y2) is equal to ______.
विकल्प
(x2 + y2)3
(x2 – y2)3
(x2 – y2)2
(x2 + y2)2
MCQ
रिक्त स्थान भरें
उत्तर
If x sin θ = y cos θ = `(2z tan θ)/(1 - tan^2 θ)`, then 4z2(x2 + y2) is equal to (x2 – y2)2.
Explanation:
Given, `x/("cosec"θ) = y/secθ = z/(cot 2θ)` = k (say)
∴ 4z2 (x2 + y2) = 4k2 cot2 2θ [k2cosec2θ + k2 sec2 θ]
= `4k^4 cot^2 2θ (1/(sin^2θ cos^2θ))` ...[∵ sin2 θ + cos2 θ = 1]
= `(4k^4)/4 ((cos^2θ - sin^2θ)/(sin^2θ cos^2θ))^2`
= (k2cosec2 θ – k2 sec2 θ)2
= (x2 – y2)2
shaalaa.com
Trigonometric Functions of Triple Angle
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