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If x sin θ = y cos θ = θθ2z tanθ1-tan2θ, then 4z2(x2 + y2) is equal to ______. -

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Question

If x sin θ = y cos θ = `(2z  tan θ)/(1 - tan^2 θ)`, then 4z2(x2 + y2) is equal to ______.

Options

  • (x2 + y2)3

  • (x2 – y2)3

  • (x2 – y2)2

  • (x2 + y2)2

MCQ
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Solution

If x sin θ = y cos θ = `(2z  tan θ)/(1 - tan^2 θ)`, then 4z2(x2 + y2) is equal to (x2 – y2)2.

Explanation:

Given, `x/("cosec"θ) = y/secθ = z/(cot 2θ)` = k (say)

∴ 4z2 (x2 + y2) = 4k2 cot2 2θ [k2cosec2θ + k2 sec2 θ]

= `4k^4 cot^2 2θ (1/(sin^2θ cos^2θ))`  ...[∵ sin2 θ + cos2 θ = 1]

= `(4k^4)/4 ((cos^2θ - sin^2θ)/(sin^2θ cos^2θ))^2`

= (k2cosec2 θ – k2 sec2 θ)2

= (x2 – y2)2

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Trigonometric Functions of Triple Angle
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