Question

In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm². What force is obtained on its piston of area of cross section 100 cm² ?

Answer 1

Force on narrow piston , F₁ = 2N
Area of cross - section of narrow piston , A₁ = 10 cm²
Let Force on wider piston be F₂
Area of cross - section of wider piston , A₂ = 100 cm²
By the principle of hydraulic machine , 
Pressure on narrow piston = pressure on wider piston
or, ${\displaystyle \frac{{\text{F}}_1}{{\text{A}}_1}=\frac{{\text{F}}_2}{{\text{A}}_2}}$

or , ${\displaystyle \frac{2}{10}=\frac{{\text{F}}_2}{100}}$

or , ${\displaystyle {\text{F}}_2=20 \text{N}}$