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प्रश्न
In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.
If AC = 4.2 cm, DC = 6 cm and 10 cm, find AB
उत्तर
We have,
BC = 10 cm, DC = 6 cm and AC = 4.2 cm
∴ BD = BC – DC = 10 – 6 = 4 cm
⇒ BD = 4 cm
In ΔABC, AD is the bisector of ∠A.
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
`therefore"BD"/"DC"="AB"/"AC"`
`rArr4/6="AB"/4.2` [∵ BD = 4 cm]
⇒ AB = 2.8 cm
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