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In δ Abc , Mn || Bc . - Mathematics

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प्रश्न

In Δ ABC , MN || BC .

If BC = 14 cm and MN = 6 cm , find `("Ar" triangle "AMN")/("Ar" . ("trapezium MBCN"))`

आकृति
योग

उत्तर

Δ AMN - Δ  ABC       {proved above in (a)}


`("Ar" triangle "AMN")/("Ar" triangle "ABC") = ("MN"/"BC")^2 = (6/14)^2 = 9/49`


`("Ar" triangle "AMN")/(("Ar" triangle "AMN") + "Ar" . ("trapezium MBCN")) = 9 / 49`


49 Ar. Δ AMN = 9 Ar. Δ AMN + 9 Ar .(trapezium MBCN) 


40 Ar. Δ AMN = 9 Ar.( trapezium MBCN) 


`("Ar" triangle "AMN")/("Ar" . ("trapezium MBCN")) = 9/40`

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अध्याय 15: Similarity - Exercise 15.1

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 15 Similarity
Exercise 15.1 | Q 6.3
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