Advertisements
Advertisements
प्रश्न
In the below fig. ABCD is a trapezium in which AB = 7 cm, AD = BC = 5 cm, DC = x cm,
and distance between AB and DC is 4cm. Find the value of x and area of trapezium ABCD.
उत्तर
Draw AL ⊥ DC, BM ⊥ DC Then ,
AL = BM = 4cm and LM = 7 cm
In ΔADL, we have
AD2 = AL2 + DL2 ⇒ 25 = 16 + DL2 ⇒ DL= 3 cm
`Similarly MC = sqrt(BC^2-BM^2)=sqrt(25-16)=3cm`
∴ x = CD = CM + ML + CD = 3 + 7 + 3 = 13cm
`ar (trap . ABCD ) = 1/2 ( AB + CD) × AL 1/2 (7 + 13) xx 4cm^2`
= 4cm2
APPEARS IN
संबंधित प्रश्न
In fig below, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8
cm and CF = 10 cm, find AD.
The sides of a rectangular park are in the ratio 4 : 3. If its area is 1728 m2, find
(i) its perimeter
(ii) cost of fencing it at the rate of ₹40 per meter.
The side of a square is 3.6 cm; find its area.
This stamp has an area of 4 square cm. Guess how many such stamps will cover this big rectangle.
How many tiles like the triangle given here will fit in the white design?
Area of design = ________ square cm
Measure the length of the floor of your classroom in meters. Also, measure the width.
- What is the area of the floor of your classroom in square metres?
An engineer who plans to build a compound wall on all sides of a house must find the area of the compound.
A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
