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प्रश्न
उत्तर
1 MSD = 1 mm
10 VSD = 9 mm
1 VSD =`9/10`mm
Least count = 1 MSD - 1 VSD
=`1/10`MSD
=`1/10` x 1 mm = 0.1 mm
= 0.01 cm
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संबंधित प्रश्न
A vernier callipers has a zero error of + 0.06 cm. Draw a neat labelled diagram to represent it.
State the purpose of ratchet in a screw gauge.
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?
Define metre according to the old definition.
(a) A vernier scale has 10 divisions. It slides over the main scale, whose pitch is 1.0 mm. If the number of divisions on the left hand of zero of the vernier scale on the main scale is 56 and the 8th vernier scale division coincides with the main scale, calculate the length in centimetres.
(b) If the above instrument has a negative error of 0.07 cm, calculate the corrected length.
What is the need for measuring length with vernier callipers?
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.
What do you understand by the following term as applied to micrometre screw gauge?
Thimble
State whether true or false. If false, correct the statement.
With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
