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प्रश्न
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3x + 2 = 0; x = 2, x = -1
उत्तर
Substitute x = 2 in L.H.S. of given equation
L.H.S. = (2)2 - 3x 2 x2
= 6 - 6
= 0
⇒ L.H.S. = 0
= R.H.S.
Substitute x = -1 in L.H.S. of given equation.
L.H.S. = (-1)2 - 3 x -1 + 2 = 0
= 1 + 3 + 2 ≠ 0 ≠ R.H.S.
x = 2 is a solution and x = -1 is not solution of the given equation.
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