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प्रश्न
Solve the following quadratic equation by factorization method : `3x^2-29x+40=0`
उत्तर
`3x^2-29x+40=0`
`3x^2-24x-5x+40=0`
`3x(x-8)-5(x-8)=0`
`(3x-5)(x-8)=0`
`=>x=8 or x=5/3`
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