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प्रश्न
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
उत्तर
Given equation is
x2 + 6x + 5 = 0; x = -1, x = -5
Substitute x = -1 in L.H.S.
L.H.S. = (-1)2 + 6 x (-1) + 5
= 1 - 6 + 5
= 6 - 6
= 0
Hence, x = -1 is a solution of the given equation.
Again put x = -5 in L.H.S.
L.H.S. = (-5)2 + 6 x (-5) + 5
= 25 - 30 + 5
= 30 - 30
= 0
Hence, x = -5 is also a solution of the given equation.
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