Advertisements
Advertisements
प्रश्न
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
उत्तर
Given equation is
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Substitute x = `(1)/(2)` in L.H.S.
L.H.S. = `2 xx (1/2)^2 - 6 xx (1)/(2) + 3`
= `2 xx (1)/(4) - 3 + 3 = (1)/(2) ≠ 0`
Hence, x = `(1)/(2)` is not a solution ofthe given equation.
APPEARS IN
संबंधित प्रश्न
A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced and the cost of each article.
Solve the following quadratic equations by factorization:
`(x-1/2)^2=4`
The difference of two natural number is 3 and the difference of their reciprocals is `3/28`Find the numbers.
Solve the following quadratic equations by factorization:\[\frac{1}{x - 3} + \frac{2}{x - 2} = \frac{8}{x}; x \neq 0, 2, 3\]
Solve the following quadratic equations by factorization: \[\sqrt{3} x^2 - 2\sqrt{2}x - 2\sqrt{3} = 0\]
Solve the following quadratic equations by factorization: \[\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 4 - \frac{2x + 3}{x - 2}; x \neq 1, - 2, 2\]
Solve the following equation: 3x2 + 25 x + 42 = 0
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3`sqrt(3)` + 6 = 0; x = `sqrt(3)`, x = -2`sqrt(3)`
Solve the following equation by factorization
x(2x + 5) = 3
Solve the following equation by factorization
`(2)/(3)x^2 - (1)/(3)x` = 1
