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Question
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Solution
Given equation is
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Substitute x = `(1)/(2)` in L.H.S.
L.H.S. = `2 xx (1/2)^2 - 6 xx (1)/(2) + 3`
= `2 xx (1)/(4) - 3 + 3 = (1)/(2) ≠ 0`
Hence, x = `(1)/(2)` is not a solution ofthe given equation.
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