Advertisements
Advertisements
Question
Solve the following equation by factorization
`x + (1)/x = 2(1)/(20)`
Solution
`x + (1)/x = 2(1)/(20)`
⇒ 20x2 + 20 = 41x
⇒ 20x2 - 41x + 20 = 0
⇒ 20x2 - 16x - 25x + 20 = 0
⇒ 4x(5x - 4) -5(5x - 4) = 0
⇒ (5x - 4) (4x - 5) = 0
Either 5x - 4 = 0,
then 5x = 4
⇒ x = `(4)/(5)`
or
4x - 5 = 0,
then 4x = 5
⇒ x = `(5)/(4)`
Hence x = `(4)/(5), (5)/(4)`.
APPEARS IN
RELATED QUESTIONS
The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is `29/20`. Find the original fraction.
Find k if x = 3 is a root of equation kx2 – 10x + 3 = 0.
Solve the following quadratic equation by factorisation.
\[6x - \frac{2}{x} = 1\]
If the equation ax2 + 2x + a = 0 has two distinct roots, if
Solve the following equation: c
Solve the following equation: `("x" + 3)/("x" - 2) - (1 - "x")/"x" = 17/4`
Five years ago, a woman’s age was the square of her son’s age. Ten years later her age will be twice that of her son’s age. Find:
The age of the son five years ago.
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
Solve the following equation by factorisation :
3x2 + 11x + 10 = 0
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
