Advertisements
Advertisements
Question
Solve the following equation by factorization
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
Solution
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
⇒ `x^2 - x - sqrt(2)x + sqrt(2)` = 0
⇒ `(x - 1) - sqrt(2) (x - 1)`= 0
⇒ `(x - 1) (x - sqrt(2))` = 0
Either x - 1 = 0,
then x = 1
or
`x - sqrt(2)` = 0,
then x = `sqrt(2)`
Hence x = 1, `sqrt(2)`.
APPEARS IN
RELATED QUESTIONS
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Solve the following quadratic equations
(i) x2 + 5x = 0 (ii) x2 = 3x (iii) x2 = 4
In a class test, the sum of Shefali’s marks in Mathematics and English is 30. Had she got 2 marks more in Mathematics and 3 marks less in English, the product of their marks would have been 210. Find her marks in the two subjects
The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.
A passenger train takes 3 hours less for a journey of 360 km, if its speed is increased by 10 km/hr from its usual speed. What is the usual speed?
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Solve the following equation by factorization
`(2)/(3)x^2 - (1)/(3)x` = 1
Solve the following equation by factorization
`sqrt(3x + 4) = x`
If `x + 1/x = 2.5`, the value of x is ______.